Write the equilibrium constant expression : CH4 (g) + Cl2 (g) = CH3Cl (g) + HCl (g)


Write the equilibrium constant expression : CH4 (g) + Cl2 (g) = CH3Cl (g) + HCl...
Chloromethane forms by the reaction CH4(g) + Cl2(g) ⇌ CH3Cl(g) + HCl(g) at 1500K, Kp = 1.6 x 104 . In the reaction mixture, PCH4 = 0.13 atm, PCl2 = 0.035 atm, PCH3Cl = 0.24 atm, and PHCl = 0.47 atm. Is CH3Cl or CH4 forming?
A-The following reaction has a Kp=1.6 x 104 at 1500 K. CH4(g) + Cl2(g) CH3Cl(g) + HCl(g) a. In a reaction mixture, PCH4 = 0.13atm , PCl2 = 0.035atm , PCH3Cl = 0.24atm , and PHCl = 0.47atm . Is the system at equilibrium? If not how does the reaction proceed to reach equilibrium? At equilibrium, the following stresses are applied. How is the equilibrium affected? Explain. i. HCl is removed. ii. CH3Cl is added iii. The volume is reduced...
Write an expression for the equilibrium constant of each chemical equation. SbCl5(g)⇌SbCl3(g)+Cl2(g)SbCl5(g)⇌SbCl3(g)+Cl2(g) 2 BrNO (g)⇌2 NO(g)+Br2(g)2 BrNO (g)⇌2 NO(g)+Br2(g) CH4(g)+2 H2S(g)⇌CS2(g)+4 H2(g)CH4(g)+2 H2S(g)⇌CS2(g)+4 H2(g) 2 CO(g)+O2(g)⇌2 CO2(g)
When 20.5 g CH4 (MM = 16.04 g/mol) and excess Cl2 undergo a reaction that has a 90.5% yield, what mass of chloromethane (CH3Cl, MM = 50.48 g/mol) forms? CH4(g) + Cl2(g) --> CH3Cl(g) + HCl(g)
Consider the following reaction at 248 C and 1.00 atm: CH3Cl (g) + H2(g) --> CH4(g) + HCl (g)For this reaction, the enthalpy change at 248 C is -83.3 kJ/mol. At constant pressure the molar heat capacities (Cp) for the compounds are as follows: CH3Cl (48.5 J/mol K) ; H2 (28.9 J/mol K) ; CH4 (41.3 J/mol K) ; HCl (29.1 J/mol K) Assuming that the Cp values are independent of temperature, calculate ∆H for this reaction at 25 C.
For the equilibrium CH4 (g)<--> 2H2 (g) + C(s) Find an expression relating the equilibrium constant, Kp, to the degree of dissociation of methane, a, and the total pressure, PTOT. Hence predict how compression would affect the more fraction of CH4 in an equilibrium mixture of CH4and H2, and graphite
The equilibrium constant expression K c for the reaction CH4 (g) + 2O2 (g) <--> CO2 (g) + 2H2O (g) is __________. A. Kc = [CO2][H2O]/[CH4][O2] B. Kc = [CO2][H2O]2/[CH4][O2]2 C. Kc = [CH4][O2]/[CO2][H2O] D. Kc = [CH4][O2]2/[CO2][H2O]2
Write the pressure equilibrium constant expression for this reaction. .NH,Cl(s)— NH3(g)+HCl(9) x 5 ?
Use the equilibrium below to answer the following questions. H2(g) + Cl2(g) # 2 HCl(g) If the initial concentration of HCl is 0.378 M and the equilibrium constant Kc = 0.223, what is the Cl2 concentration at equilibrium? Answer to 3 decimal places and be sure to include your units. Answer: Use the equilibrium below to answer the following questions. H2(g) + Cl2(g) # 2 HCl(g) If the initial concentration of HCI is 0.378 M and the equilibrium constant Kc...
For the reaction H2(g) +
Cl2(g) 2 HCl(g), the
equilibrium constant K at 800oC is 4.35 x
104.
Hydrogen and chlorine, each at a partial pressure of 0.700 bar,
are placed in a vessel at 800oC and allowed to
equilibrate. Find the final partial pressures of all three gases in
this reaction.
p(H2) = bar
p(Cl2) =
. bar
p(HCl) =
bar