Question

those join will lose, on the e on the average, 10 ise of 20 people who joined the new welche 4. A now weight-wate m any adverse 9 pounds with a sample standard deviation of random to be pounds in the first ch stowed the hypoth mean s level of significance to determine il reduction program red ing test with a 0.05 leve 28 pounds. We are conferent 10 pounds. the typical weight differ al State the Null and Alternate hypotheses b) What is the test statistic? c) What is the decision rule? d) Calculate the test statistic and interp 5. An organization that studies the use of technology among young people is interested in determining whether different age groups send different numbers of text messages per day Use the following ANOVA table to answer the questions below. Note: The table is Incompletel You will need to supply information where needed. SUMMARY Groups Ages 12-15 Ages 16-19 Ages 20-22 Count 12 12 12 Sum Average Variance 379 31.58333 40.62879 388 32.33333 44.60606 481 40.08333 43.7197 df fcrit ANOVA Source of Variation Between Groups Within Groups SS 531.5 1418.5 MS F p-value 265.75 6.182411 0.005243 42.98485 Total 1950 35 a). What are the treatments? What is the sample size? b). State the null and alternative hypotheses

Answer 1

Givon :- n = 20 X-9 pounds S-2.8 pounds Q=0.05 Ho= 10 pounds a) New hypothesis (Ho)! Uzlo Alternative hypothesis (Ho): w lo 1.0. Ho U=10 ( The typical weight loss is not different than 10 pounds) Hi! Wt 10 (The typical weight loss is different than 10 pounds ) b) Test statistics t= -elo sun = 9-10 2.8/52o ( under Ho No=10) 0.626099 1.597191 lo 5972 c) decision rule: If Itlea r than then reject Ho trab = t Ozin-1 = to.05., 20-1 = 70.025,19 - 2093 d) Here I El col = 1.5972 < trab= 2.093 so we accept the Ho. conclusion:- There is no sufficient evidence tood the typical weight loss is different than 10 pounds