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2. Assume that SAT scores are normally distributed with meanu = 1060 and standard deviation o = 195. a. If one SAT score is s
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Answer #1

2. a. Here we need to find P(x>1500)

As distribution is normal we can convert x to z

P(x>1500)=P(z>\frac{1500-1060}{195})=P(z>2.26)=0.0119

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b. Here we need to find P(\overline{x}>1500)

As population is normal as per central limit theorem distribution of sample mean is also normal, so we can convert sample mean to z.

P(\overline{x}>1500)=P(z>\frac{1500-1060}{\frac{195}{\sqrt{20}}})=P(z>10.09)=0

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