Question

12-6

A child slides across a floor in a pair of rubber-soled shoes. The frictional force acting on each foot is 20.0 N. The footprint area of each shoe sole is 16.0 cm², and the thickness of each sole is 4.10 mm. Find the horizontal distance by which the upper and lower surfaces of each sole are offset. The shear modulus of the rubber is 3.00 ✕ 10⁶ N/m².

Answer 1

G= fhear modulus = shear stress Shear strain - 12500 pa Shear shed = 20.0N 16x10-4 my 12500 Shear strain = = 12500 = 0.00416 3X106 = shear strain = 0.00416 evhere h-thickeness of the sole = 4.10 mm = (0-00416) (h) = 0.00416)(4:10) x= 0.01708 mm. The horizontal distance by which the upper loever hofone are offset = 0.08708 mm. and