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46. W A synchronous satellite, which always remains above the same point on a planets equator, is put in circular orbit arou
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Answer #1

T^2 = 4 pi^2 r^2/GM

Radius, r = (GM T^2/4 pi^2)^(1/3)

Radius of orbit, r = (6.99 x 10^7) + h

T = 9.84 x 3600 = 35424 sec

r = ((6.67 x 10^-11 x 1.90 x 10^27)(35424)^2/ 4 pi^2)^1/3

(6.99 x 10^7 + h) = 1.59 x 10^8

h = 8.92 x 10^7 m = 8.92 x 10^4 km

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