Question

Problem 4.46 Part A If the gap between C and the rigid wall at Dis initially 0.15 mm, determine the magnitudes of the support reactions at A and D when the force P = 200 kN is applied. The assembly is made of A36 steel. Enter your answer, separated by a comma. 600 mm - -600 mm -- -0.15 mm C B 25 mm ANSWER: FA, FD = kN

Answer 1

solution i Goomm-3146008 015mm mm P=200KN ta gap CD = = 0.15mm 50mm dia 25mm dia A36 sted Young's moduly - 2006 Pa Firstly we need to check whether force p is sufficient to till the gap a Ilie se change in longth due to p Als & PLAB u ş la length of AB AAB E ( A = Area of cross section - ID² E = 200 Gpa. S Ol = 200x10x Goo Pla 5 = E= stress E са ти да JA De=PL 502 x 200x103 AE al = 0.305 mm tortes will develop Al > Agap=0.15 mm 8 Reaction at AD FA Total change in length of Bar = 0.15 mm. ARAB + AlBC - O. 15 mm PAB LAB & PBC ABC = 0.15. AAB ABLE

» PABE FA ; PBC - fut P ' put P=20080 FA (600) → (fat B) 600 = OLS 1 25²x 200x 103 2502x200x1037 Falboo A = 39.25 + 5 502 Gat 200x103 252 FA = 140375N FA=-140•375 KN . FA = 140.375 KN) and FA+P+ fp =0 - 140.375 + 200 + FD =D fo=– 59.625KN &. for 59.625 kn FA, F = 140.375 KN, 59.625 KN ) Answer