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What is the metal ion in a metal nitrate solution M(NO3)4 if 90.52 g of metal...

What is the metal ion in a metal nitrate solution M(NO3)4 if 90.52 g of metal was recovered after 4.00 hours of electrolysis at a constant current of 22.8 A? Enter the chemical symbol of the element, with correct capitalization. [F = 96,500 C/mol e–]

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Answer #1

Use first law of faradey

// M(NO3) - mt4 tunog E= M = Equivalent mans (MB=molecular mans) (gn) [w= 20 = &- it W = 20 w= 90.52 g W = 90.529 t= 4000x360// M(NO3) - mt4 tunog E= M = Equivalent mans (MB=molecular mans) (gn) [w= 20 = &- it W = 20 w= 90.52 g W = 90.529 t= 4000x360

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