Question

It is desired to distill two feeds 1 and 2 of water (W) and acetic acid (A) mixture as shown in the Figure below. Calculate the theoretical stages required for the distillation separation at 1.0 atm. Distillate 98 mol% water LID = 1.2L/Dmin Feed 1, bubble-point liquid kgmolh 75 25 1 atm 100 Feed 2, 50 mole % vaporized kgmol/h 50 50 100 Bottoms 95 mol % acetic acid Steam L WATER ( WACETIC ACID (A), 1 ATM Xw 0.0055 0.053 0.125 0.206 0.297 0.510 0.649 0.803 0.9594 yw 0.0112 0.133 0.240 0.338 0.437 0.630 0.751 0.866 0.9725

Answer 1

Solution! distillate 98 mol % wates =1:2 (412) mein Feeds bubble point lig 100 kmoller Feed 2 50 mol% vapor lookmolar Bottoms 9.5 mol% acetic acid w Given that OS feed (1) composition. (for water) , 0.75 feed 2 composition for water) Mre = 0.5 Distillate composition ( fere water) no = 0.98 Bottoms composition fore water Mw=0:05 Reflux ration R = L = 1.2 Romin) .. Applying overall balance. fut F2 = DtW A+W=2000

Applying water balance 0.75XFito.5 F2 = 0.98 A + 0.05w 0.75X100+ 0.5X100 = 0.98 +0.05 W 75+50= 0.980 +0.05w - .. D = 123.65 kmol has W = 46.34 kmollar feed 2 is 50 mol % Vapotúzed. n . 2 = 0.5 1- 0.5-1. 4. Slope of a line = 1-1 =7 .. slope = obc= -1 tan o = -1 o = tan '(-1) O = -45°)

from graph intercept = 0.98 = 0.27 Remoth Romio = 2.62 - Intercept of upper operating line. Intercept = 2. R=1-2 Rmeio = 1.272.995 R=3.144 Intercept = 0.98 3.144 tl Intercept = 0.236 ... from the graph number of theritical stages required In = 16 troys Answer

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