Question

ample 12.9.1 Figure 12.9.4a shows the details of an extruded aluminum 7075-T6 section, for which E = 10.5 x 106 psi Hocy = 70,000 psi. Calculate the crippling stress. The section is resolved into five rectangles, as illustrated in Figure 12.9.4(b). The corner (and fillet) areas are omitted. 0.75" 10.09375" 1 T 0.25" - 0.0625" 2" x --- 0.09375" || 0.25" 1" -XT 1x = 0.182 in. A = 0.2855 in.?

Answer 1

Rakines formala oeg. A erippling load = a (parimes constant) ΠΕ 70/000 TTx (10.5X106) A=6755x104 Kaj 0:182 U 0.2855 K-0.798 осу. tallet coippling stress - 70,000 _ 1 + 6-755x16 ( ) 0-798 If length of column Le=2in 70,000 crippling Stress = 1+ 67554164(6-798) Tipping Stoess = 69704-24 psi