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99 Marks: 1 What is the mass (in grams) of the solid product when 6.83 g...

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What is the mass (in grams) of the solid product when 6.83 g of iron(II) nitrate reacts in solution with excess sodium hydroxide?

Fe(NO3)2(aq) + NaOH(aq) --> Fe(OH)2(s) + NaNO3(aq) [unbalanced]

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Answer #1

Fe(NO3)2 + 2 NaOH= Fe(OH)2 + 2 NaNO3(aq)

Moles of Fe(NO3)2 = mass / molar mass

= 6.83 / 180

= 0.038

Moles of Fe(NO3)2 = moles of Fe(OH)2

= 0.038

Mass of Fe(OH)2 = mole * molar mass

= 0.038 * 90

= 3.42 grams

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