

Book: Chenming Hu. Modein Semiconductor Devises for integreted circuits Chapter 4,8 (in the theory parts I...
A pn junction diode is made of a new semiconductor with 10^16cm-3 donors in the n side and 2x10^17cm-3 acceptors on the p-side. Intrinsic carrier concentration is same as silicon 10^10cm-3at room temperature. Let's assume that a forward bias voltage is applied in a way that it create following minority carrier concentrations in quasi neutral regions. p(x) =10^4 + 10^14/[1+10^4(x-xn)] (cm-3) where x>xn>0 and n(x) = 500-10^15/[10^4(x+xp)-1] (cm-3) where x<-xp<0. x is given in cm scale. Calculate the total current...
A pn junction diode is made of a new semiconductor with 10^16cm-3 acceptors in the p side and 2x10^17cm-3 donors on the n-side. Intrinsic carrier concentration is same as silicon 10^10cm-3 at room temperature. Let's assume that a forward bias voltage is applied in a way that it create following minority carrier concentrations in quasi neutral regions. n(x) =10^4 - 10^14/[10^4(x+xp)-1] (cm-3) where x<xp<0 and p(x) = 500+10^15/[10^4(x+xn)+1] (cm-3) where x>xn>0. x is given in cm scale. Calculate the total...
this is a problem of semiconductor device and
fundamentals.
Problem 4: pn Junction Current Distributions Consider a Si pn step junction diode maintained at room temperature, with p-side and n-side dopant concentrations NA 1016 cm3 and Np-2x1016 cm3, respectively. (You may assume that each side is uncompensated.) The minority carrier recombination lifetimes are τ,-10-6 s and τ,-10-7 s on the p-side and n-side, respectively a) Calculate the minority carrier densities at the edges of the depletion region when the applied...