If the concentration of Mg2+ ion in seawater is 1.21x103 mg/L, what OH- concentration is required...
If the concentration of Mg2+ ion in seawater is 1.21x103 mg/L, what OH- concentration is required to precipitate Mg(OH)2 ?
Ksp(Mg(OH)2)=5.6x10-12
-OH concentration must be greater than _____ M.
Homework Answers
![solution :- Concentrates af mg t= 1-21x10 mg/ = 1-219/2 = 1.21 La moya = 0.05042 mol [mg2+] = 5:042x102 moye [or] =? Ksp melo](http://img.homeworklib.com/questions/181597f0-aab8-11eb-944e-e99e4ec6c3c0.png?x-oss-process=image/resize,w_560)
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If the concentration of Mg2+ ion in
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Ca(OH)2 is added to water to reach a concentration of
53 mg/L. Initially, the water had 3.09 mg/L of Mg2+ and
it reacts with Ca(OH)2 according to equation 61a. Assume
SO4-2 is in excess. What are the final
dissolved Ca2+and Mg 2+ concentrations? What
is the initial and final hardness? What is the Mg(OH)2
precipitate concentration? (28.6 mg/L, 0 mg/L, 12.5 mg CaCO3/L,
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