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© Submit All Questions Completed 3 out of 22 01 08 - Save Answer HRNC Question 4 of 22 A compou..is 54.53% C, 9.15% H, and 36.32% O by mass. What is its empirical formula? Insert subscripts as needed. empirical formula: CH 01 The molecular mass of the compound is 132 amu. What is its molecular formula? Insert subscripts as needed. molecular formula: CHO SPECIAL AEO um (g) 0 0 → = privacy policy Terms of use Contact us help

Answer 1

if we took loo g ob Compound, mass ob mass of mass of c = 54.53 g H = 9.15 g o=36.329 and molar mass of c = 12.01 molad g/mol mass of it = 1.008 g/mol molar mass g o = 16.00 g/mol mola mass molao mass mols ob c = su.53 g 12.01 Ghoul -- 4.54 mol c mols of H = 9.15g Y 1-oo8 9) med = 9.06 molt mos os o = - 86-32g Co =2.27 molo 16.00 g/mol

in for belative compasision divide above rol them. values 3 among ic with Leoff mol value 2.27 mol 4.54 2.27 H = 9.06 ru 2-27 och 27 -1 . Empirical fromla - C Huo molas mass of molecular formula =1329 Cmim molas mass of Empirical formula = 44.1 g/mol 1 l G huo - mol isano - mom of molecular formula _132 m.m or Empirical format unel - 3 .:. molecular formule; - C. 2x3 tux3 vya ...Ag)- Emfisicd:- 1 Celebs H12 07 :: A)- Empirical:-|C2H40 To Hin O3 molecular