Question

calculate the molarity of each of the following solutions

1- 0.54 mole of BaCl₂ in 100.0mL of solution

2- 0.230 mole of Na₂CO₃ in 200 mL

3- 0.325 mole of C₆H₁₂O₆ in 250.0 mL

4- 1.384 mole of KNO₃ in 250.0mL

Answer 1

Molarity has the equation:

M = mol of solute / Liter of solution

1)

M = mol/L = 0.54 / 100 ml = 0.54 / 0.1 L = 5.4 mol per liter

2)

M = mol/L = 0.23 / 200 ml = 0.23 / 0.2 L = 1.15 mol per liter

3)

M = mol/L = 0.325 / 250 ml = 0.325/ 0.25 L = 1.3 mol per liter

4)

M = mol/L = 1.384 / 250 ml = 1.384 / 0.25 L = 5.536 mol per liter

NOTE that mol per liter is equivalent to "Molar"