Question

Leroy, a starting player for a major college basketball team, made only 27.5% of his free throws last season. During the summer he worked on developing a softer shot in the hope of improving his free-throw accuracy. In the first eight games of this season, Leroy made 29 free throws in 40 attempts. Let p be his probability of making each free throw that he shoots this season. (a) State the null hypothesis H. that Leroy's free-throw probability has remained the same as last year and the alternative Ha that his work in the summer resulted in a higher probability of success. Ho: P -Select-- Hai --Select- (b) Calculate the z statistic for testing H, versus H. (c) Find the p-value. p-value = Do you fail to reject or reject H, at the a = 0.05 significance level? Reject H. There is sufficient evidence that the alternative hypothesis is true. Do not reject Ho. There is sufficient evidence that the alternative hypothesis is true. Do not reject Ho. There is not sufficient evidence that the alternative hypothesis is true. Reject Ho. There is not sufficient evidence that the alternative hypothesis is true, (d) Give a 90% confidence interval for Leroy's free-throw success probability for the new season. Are you convinced that he is now a better free-throw shooter than last season? yes Опо

Answer 1

Andwer - PageNo 0 Plhat) = 29 40 = 0.425 n=uo HO! P-0215 Hl:p>0.25 tail test -005 Z Value . z=(pChat) -P) 1.5px (6) = (0.425 -0.245) 10.245 x 425 40 vo.ats (18. oius v4.984375

Pagenol - 0.45 2:23a571384 0.201561304 2=0.2015) Pal-P(Z >0.2015) = 0.4 202 P value = 0.420 a Pialue > Alpha fall to Reject to 0.4202 > 0.05 Do not Reject Ho, there is not sufficient evidence that the alternate hypothesis is true Proofas 950.275 n = 40

Pageno for 904. confidence level 2 = 1695 Magiu of er or E= z[xla) x JPG CHO = 4.645 Joxas Coats) 1.645% 00406 . ='0.1161 907. contidence inteavad for population =(P-E, P+E) RE=0.435 -0.1161 = 0.6089 P+€ = 0.405 +0:1161 for 90% confidence interval = (0.6089, 0.8411)

Page No Yeş lower limit of 90 confidence level is higher than 24.57