Question

5. A differential op-amp circuit needs to be designed to implement linear voltage measuring function =2.261, where input voltage is the differential output voltage measurement V.-.-V, of a Wheatstone bridge circuit in stage-1 signal conditioning (1) Provide values of resistors that define the circuit's gain as A (2) Proved the required values of input voltages and V. of the designed differential op amp circuit (3) Provide the schematics of the designed stage-2 differential op-amp circuit and its connection to the given Wheatstonebridge circuit of stage signal conditioning

Answer 1

solution : Given date. vout= 2.26 V2 where Va is the differential output vollage measurement - Vx= VA-VB. Solution : opamp output is Vo - Av[ VA-ve] Ar is the voltage gan vout : AVC VA-VR] > For problem-1. Given the Av= R2 In problem Given Vout= 2.266a vout =226CVA-ve]> compare equation 1 with @ Ava Re = 2:26 . R2 = 2.26R, must choose R2 as 2.26 times of R..

solution VA-V Because In Question mention R VA is Input of op. Amp mention VB is B = V2 B Because In Question Input of op-Amp. .: VARVRB X V3 RBURA VB = V2 = ROXVS ROIRC => Vy-V2 = rs IRB - RD 7 RBIRA ROIRC Katas-V2 = VA-VB = V8 [ RB RO7 IRBIRA ROIRC If TRARD=RBRC Then vi = V2 VA - VB Soluhont Schematic Diagram of the designed stage -2 differential opamp& its connection is Given to wheatstone Bridge circuit of stage-1. RB A4 Vout op. Amp