Question

I know how to do number one just not number 2. Please answer number 2 only

Write a java program that will print out following pattern. Use nested for loop. 2. Add a method to the above program that generates takes two numbers as parameters and prints out all the numbers from number 1 to number 2 separated by using a while loop. (Do not print the last ,'). For example: Calling method1(9,51) should print: 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51 Calling method1(5,1) should print: 5, 4, 3, 2,1

Answer 1

public class HourGlass {
  public static void method1(int num1, int num2){
    if(num1>num2) {
      for(int i = num1;i>num2;i--){
        System.out.print(i+",");
      }
      System.out.println(num2);
    }
    else {
      for (int i = num1; i < num2; i++) {
        System.out.print(i + ",");
      }
      System.out.println(num2);
    }
  }
  public static void main(String[] args) {
    int size = 3;
    int n = 2 * size - 1;
    for (int x = 0; x < size; x++) {
      for (int y = 0; y < x; y++) {
        System.out.print(" ");
      }
      for (int i = 0; i < (n - x - x); i++) {
        System.out.print("*");
      }
      System.out.println();

    }

    int t = size - 2;
    while (t >= 0) {
      for (int x = 0; x < t; x++) {
        System.out.print(" ");
      }
      for (int y = 0; y < (n - t - t); y++) {
        System.out.print("*");
      }
      System.out.println();
      t -= 1;
    }

    System.out.println("\n");
    method1(9,51);
    method1(5,1);

  }
}

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