Question

An open U-tube has water to a height h on both sides, as shown. The cross-sectional area of the left-hand tube is A1 = 1.50 cm2, and that of the right-hand tube is A2 = 0.50 cm2. A light oil (which does not mix with water) with a density of 0.83 g/cm3 is added to the right-hand side. When equilibrium is reached, which of the following is correct?

PLEASE DONT COPY AND PASTE THE SOLUTION FROM THIS QUESTION THAT HAS ALREADY BEEN POSTED. I don't understand it, so some explanation would be nice! Thank you! Answer is A by the way

An open U-tube has water to a height h on both sides, as shown. The cross-sectional area of the left-hand tube is A1 1.50 cm2, and that of the right-hand tube is A2 -0.50 cm2. A light oil (which does not mix with water) with a density of 0.83 g/cm'is added to the right-hand side. When equilibrium is reached, which of the following is correct Quiz10 5.png?_&d2lSessionVal-dEg9V2Emwo7 A) The level on the right-hand side is higher than that on the left. B) The level on the right-hand side is lower than that on the left C) The levels of the two sides are the same D) The difference in the heights depends on A1 and A2.

Answer 1

We know the pressure is expressed as follows: P = rho g Z The density of the oil is less than the density of water. From the both equations, we have as follows: P_1 + rho_oil gh + rho_water dg - rho_water gD - P_2 = 0 rho_oil gh = rho_water g (D - d) rho_oil/rho_water = (D - d)/h (D - d)/h < 1 Thus, the level on the right hand side is higher than the left hand side.