Cylinder A has a downward velocity in m/s given by VA=p3 – 42, where t is...
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Cylinder B has a downward velocity in feet per second given by V_B = 2t^2 + t^3 where t is in seconds. Calculate the acceleration of A when t= 2 seconds. Car A is moving east at the constant speed of 36 km/hr. As car A crosses
1. At a certain instant, cylinder A has a downward velocity of 0.8 m/s and an upward acceleration of 2 m/s. Determine the corresponding velocity and acceleration of cylinder B.
The velocity ofa particle is defined by v (-2i+(3-20A, m/s where t is in seconds. If r 0 when t 0, determine the displacement of the particle during the time interval t As (-8/-4A, m As (-6i+-6A. m As (-10/-2A.m As-(-4, m 1 s and t 4 s. A motor gives a disk A an angular acceleration of aA (2t+3) rads, where t is in seconds. If the inidal angular velocity of the disk is Dg 5 rads, determine the...
A Review The roller at A is moving with a velocity of va = 4 m/s and has an acceleration of aA = 2 m/s² when A = 3.7 m (Figure 1) Part A Determine the velocity of block B at this instant. Express your answer to three significant figures and include the appropriate units. Enter positive value if the velocity is upward and negative value if the velocity is downward. I Å R O ? vB = Value Units...
A stone thrown downward with an initial velocity of 34.3 m/sec travel a distance of s meters, where:s(t)=4.9t + 34.3t and t is in seconds. If a stone is thrown downward at 34.3m/sec from a height of 294 m, how long will it take the stone to reach the ground?I am putting 294 in for t and trying to solve it that way. Is this correct? If not please let know where I am going wrong.
I can't get part B
The cylinder is displaced 0.18 m downward from its equilibrium position and is released at time t = 0. Determine the displacement y and the velocity v when t = 2.2 s. The displacement and velocity are positive if downward, negative if upward. What is the magnitude of the maximum acceleration? K= 147 N/m Equilibrium position m = 4.0 kg Answers: When t = 2.2 s: ya 0.129 When t = 2.2 s: V =...
the velocity of a particle is given by v=[16t^2i+4t^3j +(5t+2)k]m/s, where t is in seconds. If the particle is at the origin when t=0, determine the magnitude of the particle's acceleration when t=2s. What is the x,y,z coordinate position of the particle at this instant.
Given s(t) = 2+ + 4t, where s(t) is in feet and t is in seconds, find each of the following. a) v(t) b) aſt) c) The velocity and acceleration when t= 2 sec a) v(t) = b) a(t) = c) When t = 2 sec, the velocity is (Simplify your answer.) When t = 2 sec, the acceleration is (Simplify your answer.)
Given s(t)= +2t, where s(t) is in feet and t is in seconds, find each of the following. a) v(t) b) a(t) c) The velocity and acceleration when t=2 sec a) v(t)= b) a(t)=0 c) When t= 2 sec, the velocity is | (Simplify your answer.) When t = 2 sec, the acceleration is (Simplify your answer.)
A disk is rotating around its center at an angular velocity of = (5+2+6) rad/s, where t is in seconds. Calculate the magnitude of the velocity and acceleration of point A when t = 0.5 S. Point A is on the disk as shown. 0.8 m a) va = 1.31 m/s aA = 2.21 m/s2 Ob) va = 4.22 m/s a A = 8.32 m/s2 Od VA = 6.15 m/s aa = 4.86 m/s2 O d) va = 2.60 m/s...