Question

a poll of 2094 randomly selected adults showed that 94% of them own cell phones

A poll of 2,094 randomly selected adults showed that 94% of them own cell phones. The technology display below results from a test of the claim that 92% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e). Test of p = 0.92 vs p*0.92 Samplex N Sample P 95% CI Z-Value P-Value 1965 2,094 0.938395 (0.924861,0.951929) 3.10 0.002 a. Is the test two-tailed, left-tailed, or right-tailed? Right talled test Left-tailed test Two-tailed test 1 b. What is the test statistic? The test statistic is a (Round to two decimal places as needed.) c. What is the P-value? Click to select your answer(s). STICA Ne - E O pe here to search

Answer 1

he have in the question given n= 2094 (Sample size) Þ= 9440 = 0.94 (Sample Proportion) llevel of significamu) 2 0.01 Our Hypothesis is Но! P=0.92 Hii P +0.92 (I wo tailed test) Is CI) test the o Two Tailed test b) The test 1 z Statistics is ľ - P Pllap) n Za 0.94 -0.92 0.92) (1-0.92) 2094 za 3370 test statistic value o of CScanned with CamScanner

C) P value เร the tail end' probability, P(12173.37) P-value = -3.37 3.37 P-value =0. 000752 a) HO: P=0.92 ос Ryect the Noll Hypothesis because P-value is less than significance level a equal to the OB There is not sufficicut evidence to support the claim that 92% of CScanned with CamScanner adults owns a cell phone.