Question

Java

1. (5) Assume selection sort is applied to the following array. Show the state of the array after the first pass of the outer loop. 50 35 15 100 90 20 10 25 2. (5) Assume bubble sort is applied to the following array. Show the state of the array after the first pass of the outer loop 50 35 15 100 90 20 10 25 3. (5) Assume quicksort is applied to the following array. Show the state of the array after quicksort has partitioned the array. Use the element in position 0 as the pivot value. 50 35 15 100 90 20 10 25 4. (5) Assume radix sort is applied to the following array. Show the state of the array after the first pass of the outer loop

Answer 1

, selection so㎡rg es an algoo7thm on when ate cop frnt valueto the Seeond talue and ke frit value and third alyer compase values and place srone value a 0th ,ndex and soon ts mot Heache d at n index The Slat aqain frorm Index 1 upro -4 index Take second Value and third Values compuse these alues and placa small et value at 1st Indlex oon The algorithm The alg oxithmox the same step flexetivery Unf elements ae not Sorted

up

Giten Away Ra 50 36 5 1o0 9o 20 88 0 25 5S 56735 upap CYe) 35 50 15 100 до 2088 Ib 2S55、 3671S 1S 5o 5 (00 9 20 88 25 5 1bo NO (5 5o 35 t00 9o 20 88 0 25 55 59o NO 9o 20 83 (0 25 55 15 5 85 o0 20 5> 20 5 50 35 00 90 208 O 25 S 157 88 No 25 55 15 50 35 00 go 20 88 CYe

lo 50 35 o0 90 20 88 25 55 0 5 50 35 l00 90 20 88 IS 2s 5S 10 50 35 100 go 208815 오555 lo>S5 No o 50 3 0 90 88 15 25 5S Stake of the artay afteu the fist pacu of the auteri toop 50 5 (98S555 Q. Bubble Sont Bubble s an compastng fiut too value and put the age one at highes Index Then we take next teoo values compave thee Value and place lasge value at hig Theae proceise do Tresavely uni the ages ake hes index Then stobt ng les ton o to N-2 nex t pud large one at hisher inde

Given Aray 50 35 15 10o 9o 20 38 to 25 55 Pass 5o 35 15 too 9o 20 8 0 25 55 50>35 → suap CYES) 35 5 15 100 90 0 83 o 5 55 50>15 →soap CYES) 35 15 5 too go 2 88 10 25 55 507100 NO) 35 IS 50 too 90 20 88 10 25 5 CYES) 35 15 50 9 (00 20 33 0 5 5S CYES) 25 15 50 до 20.100 88 10 25 55 CYES)

35 15 50 до 20 88 (00 10 25 55 3 5 50 90 20 88 10 10025 S5 CYES) 35 15 50 9 20 8 lo 25 100 55 CYEs) 25 15 50 90 20 88 10 25 5540 State of the asra y afteu the faPas ot the 35 | 15 | 50 | 90 | 20 | ㅱ8 | 10 | 25 | 55 | 100

Each re와ation of Kroon a the PNot and divides the l s+ īnto2 roLpS the quiceso sele crs an element rDepshePVo . Elemenh5 uo hose key. ayte iets than (on equal to) -me ra 'The Pivot- element Biements uwhase keys ave greae than (or equal to) te Gwen Anay:- 50 35 5 (o 9o 20 28 0 25 5S The findex left, stant, at-the second element and 3ight stast at the last elemen H ト Pointe. Fs set +oendexg

euant to TOOe al of the elemen ks smalley than the Pivo to the left pait o the and all oF the etement lauger than the o move elt to sight , skippng ovex elener aute Smalles than the Pi Voh isha 35 5 o 9o 88 IO 25 5 S gh 50 35 15 o o 88 lo 25 5S がght . Pivot le then mole might to the lebt, scipping oven elements tha asue egter than he prvo 50 35 15 0 9o 20 83 o 2 night Pivot lett

then tebt and stght have Sto ppedlebt s n an element greae than (or eual to) the piVat and sight onan elament imae than (ou equa) the Pivot 5 59o 20 83 o 25 55 Pivot a lebt to the lest o Atght, foe element ane stuapped 50 35 1S 25 9o 20 3 o 0 5s Pvot ve then epeat the Proces untt estrht CHoYs. Flat move lebt then ght 50 35 15 25 9 20 83 lo 100 5S ett ight Pvot

50 5 1S 5 to 0 88 90 6o S5 Pvot hight Again xepent tme Ap 15 25 lo 20 g89D to o 55 ight eb Nouo eht and ight have Hosed each oither The tinal pav tho Pavtt to a ap the pYot element oth ht 20 35 15 25 10150188 90 loo SS Note tha qtl eleme n b to the (ett- 06 the pivo- ave lexs n equal to) the Pot and as elemenb to tne ight o the prvot are gregtel tha a equal to) tha pivot

2 0 05o50 3 90 100 aax ethe tinea. sorting al geri thna on each dfait for eachop the digit in the umbe Hooeveu is Someuohat eeel counterfntuitive, in the sense that the mm bers ave sated on the least-signifcan dgit fust followed by the second -teast signi frant di and So on t the most Signihi cant dib , the poten adoped by thts sort method

Given Aroay 5o 2 5 16 Pa8s 82 2.5 55, gA 2 3 4 5 50 g 32 2. 2S 20