Question

to the plane of a loop of radius 3 cm, resistance 0.3 2, and negligible self- increasing at a rate of 40 mT/s. Find the following values (c) the rate of Joule heating in the loop

Answer 1

A uniform magnetic field vector B is established perpendicular to plane of a loop of radios 3cm a) The induced emf = mod (A d phi B)/dt cmf = mod (d/dt (BA)) = mod (+ A (dB/dt)) = pi r^2 (40 mT/s) = pi (0.03)^2 (40 times 10^-3) emf = 0.036 times 10^-3 emf = 3.6 times 10^-3 v b) Induced current I = emf/R = 3.6 times 10^-3 /0.3 \r\n I = 12 times 10^-3 A c) joule heat p = T^2 R = (12 times 10^-3)^2 times (0.3) p = 4.32 mu W