Question

Write a C program that prints the numbers from 1 to 100, but substitutes the word “fizz” if the number is evenly divisble by 3, and “buzz” if the number is divisible by 5, and if divisible by both prints “fizz buzz” like this: 1 2 fizz 4 buzz fizz 7 8 fizz buzz 11 fizz 13 14 fizz buzz 16 17 fizz 19 buzz ... and so on

Answer 1

#include <stdio.h>

int main()
{
int i;
  
for(i=1; i<=100; i++){
if( i % 5 == 0 && i % 3 == 0){
printf("fizz buzz\n");
}
else if( i % 3 == 0){
printf("fizz\n");
} else if( i % 5 == 0){
printf("buzz\n");
} else{
printf("%d\n", i);
}
}

return 0;
}

Output:

sh-4.2$ gcc -o main *.c   
sh-4.2$ main
1   
2   
fizz
4   
buzz
fizz

7   
8   
fizz
buzz
11
fizz
13
14
fizz buzz   
16
17
fizz
19
buzz
fizz
22
23
fizz

so on