Question

12, 18 thank you

- - _12) Numerical coefficients that correctly balance the reaction, Fe + H20 Fe3O4 + H2 are, A) 3,4, 1,4 B) 3, 1, 4,4 C) 3, 5, 2,4 D) 1.3, 4,4 13) The word equation "calcium reacts with chlorine to produce calcium chloride" would be represented by which of the following formula equations? (a) CaCl2 +CaCl2 (b) CaCl2 Ca+ Cl2 (c) CaCl2 +CaCl2 (d) Ca+ Cl2 -CaCl2 _14) Which of the following is a decomposition reaction? a) PbCO; (5) PbO (s) + CO2(g) b) CaO (8) + CO2 (g) - CaCO3 (8) c) Mg (8) + O2 (8) MgO (8) d) CH4 (8) + O2(g) - CO2(g) + H2O (1) 15) Which one is a double-replacement reaction? (a) 2 Mg +02 - 2 Mgo (b) NH4C-NH3 + HCI (c) 2N2+3 HH2 NH3 (d) Cd(NO3)2 + Na.S CdS + 2 NaNO; 16) Which one most correctly represents a combustion reaction? (a) 2 Mg + O2 - 2 Mgo (b) NHACI - NH3 + HCI (c) 2 N2 + 3 H2 - 2 NH3 (d) Cd(NO3)2 + Na2S - CdS + 2 NaNO, 17) What are the coefficients that will balance this reaction? HI (aq) + Ca(OH)2 (aq) → H20 (1) + Calz (aq) a) 1,2,2,1 b) 2, 1, 2,1 c) 2, 2, 1, 1 d) 2, 1, 1, 2 18) What is the value of "x" in the following equation? CH4 + _x_02 → CO2 + H2O a) 4 b) 9.5 c) 16 d) 8 e) 10

Answer 1

solution (12) Fe + H₂O Fe3O4 + H₂ First balance the Fe in both side is Fe Land side in left 3 multiply by we get. 3Fe + H₂O - Fe3O4 + H₂ 0 balance the atom in both side 4 to H2O left hand side we get 3Fe + 4H20 Fez 04 + H₂ second, multiply by in sight both side hand side Third, balance H atom in me-pe 4 4 in H2 we get 3Fe + 4H2O 4H2 Fe₂O4 + This is balance chemical reaction. AnS = (A) 3,4, 1,4

(18)= C6H14 t no2 CO2+H2O First we have to multiply by balance C atom in both side in CO2 in LAS (left hand side) we C6H14 + 02 6 Co2+ H2O H atom in both side 7 in H2O in L.H.S. Second, balance the met le get, CH14 + O2 we -> 6602 + 7H20 because 19 Third, balance the o atom in bath side multiply by 19 in O2 in Right hand side atom is present in Left hand side get, C6H14 6CO2 + 7H2O O so we + lg 02 On C6H14 + 9.502 > 6CO2 + 7H2O This is the balance n=9.5 chemical reaction Ans (6) 9.5 SO