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Critical numbers occur where h(t) = 0 and where h(t) is undefined. 3+1/2 - 4 0 = h(t) = 42-3/4(3+/2 – 4) = 493 when the nu

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n(t) = 3 t2_4 44/73 ń (+)=0 3 +12_4=0 t = (3)= 9 h(t) is not defined for t=0 s. The critical points are t = 16 9 0 2

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