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For the reaction 2802(g) + O2(g) -2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K...

For the reaction 2802(g) + O2(g) -2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K The equilibrium constant for this reaction at

For the reaction 2802(g) + O2(g) -2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K The equilibrium constant for this reaction at 277.0 K is Assume that AH° and ASº are independent of temperature.
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For the reaction 2802(g) + O2(g) -2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K...
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