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14. A 1kg mass goes down a slide which then puts it into a loop-the-loop of radius 1m. a. At the top of the loop, the normal

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Thanks for asking ..R=IM a) let this mass s Hthing h ANA height A. my VA = Szgh given, Ne =N 2. mg tNe-mve 1x9.8 +5 = IXVR Conservation, IBethweeUsing wnk. (between Point A&B) -enerry, -mgloR)= bmvt ** Xlo x9.8xh (14.8) + 1f.8 h= 7,2253 m) Amd d) at botum. 10x9-8x7.2253

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