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Hi everyone, I need help in Haskell, please. Write a Haskell function that takes an Int...

Hi everyone, I need help in Haskell, please.

Write a Haskell function that takes an Int i as its only parameter and uses a list comprehension to caclulate m(i) = 1 + 1/2 + 1/3, ... + 1/i

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Answer #1

Program:

calc_m j = sum [1/i | i <- [1..j]]

main = do
print(calc_m 10)

Screenshot: ( for reference )

calc_m j = sum (1/i | i <- [1..]]] WN main = do print(calc_m 10)

Output:

2.9289682539682538

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Note: If you have any doubts please comment.

It will be great help If you like.

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