Question

Write a function called ArrrayScalarM(...) that multiplies each element of an array by a scalar (constant integer value). The function takes in three arguments: an integer array, the size of the array, and the scalar. Test the function, by calling it from the main program. You can initialize the array as follows:

int arrN[10] = {4, 0, 453, 1029, 44, 67, 111, 887, 4003, 1002};

Answer 1

The C code for the function and its implementation is pasted below.

/**
* C program to multiply all elements in an array with a scalar
*/

#include <stdio.h>
void ArrayScalarM(int a[],int n, int s); //function prototype

int main()
{
int i,s,n=10;
int arrN[10]={4,0,453,1029,44,67,111,887,4003,1002};

/* Input a scalar */
printf("\nEnter a scalar: ");
scanf("%d", &s);
/* Call the function to multiply elements of array with a scalar */
ArrayScalarM(arrN,n,s);
return 0;
}
void ArrayScalarM(int a[],int m,int s)
{
int i;
printf("\n Array multiplied by scalar\n");
for(i=0; i<m; i++)
{
a[i]=a[i]*s;
printf("%d\n",a[i]);
  
}
return;
}

The output screen is pasted below.

Enter a scalar: 2 Array multiplied by scalar 8 O 906 2058 88 134 222 1774 8006 2004