Question

Find the potential difference across each resistor in the figure below. (R_1 = 540 ohm, R_2 = 4.20 ohm, R_3 = 2.80 ohm, R_4 = 2.20 ohm) Delta VR_1 = Delta VR_2 = Delta VR_3 = Delta VR_4 =

Answer 1

From the given question,

12 12.0V .00V 18.0V Loop Loop 11+12 4.20 Ω 5.40 ΩΚ, R2 R, 2.20 Ω 2.80 Ω, R3

From Loop 1

12-3-(I₁+I₂)*4.2-5.4*I₁=0

9-9.6I1-4.2I2=0

9.6I₁+4.2I₂=9

I₂=(9-9.6I₁)/4.2

From loop 2

18-3-(I₁+I₂)*4.2-2.8*I₂-2.2*I₂=0

15-4.2I₁-4.2I2-2.8*I₂-2.2*I₂=0

15-4.2I₁-9.2I₂=0

4.2I₁+9.2I₂=15

4.2I₁+9.2[(9-9.6I₁)/4.2]=15

solving we get

I₁=0.28 A

I₂=1.5 A

$\Delta V_{R1}$=5.4*0.28=1.512 V

$\Delta V_{R2}$=4.2*(0.28+1.5)=7.476 V

$\Delta V_{R3}$=2.8*1.5=4.2 V

$\Delta V_{R4}$=2.2*1.5=3.3 V