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Dissociation of Ag2CrO4 can be represented as
2S S where S=solubility
solubility product of Ag2CrO4 ,Ksp=9.00 x 10-12
K2CrO4 Dissociates to give K+ and CrO4-2 ions
K2CrO4 2 K++ CrO4-2
initial concentration 0.414M 0 0
change 0.414 - 0.414 0+2x0.414 0+0.414
final concentration 0 0.828 0.414
solubility of Ag2CrO4 will be decreased when K2CrO4 is added .it is due to common ion effect .common ion is
when K2CrO4 is added
S+0.414 [CrO4-2 ] = S+0.414 M
Ksp= [Ag+]2[CrO4-2 ] = 9.00 x 10-12
9.00 x 10-12 = S X [S+0.414] Solubility,S= 9.00 x 10-12 / [S+0.414]
=9.00 x 10-12 / 0.414 S<<<< 0.414
Solubility,S= 2.1739 X 10-11 M
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