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CH(CH),CH) will react with gaseous oxypen (0) to produce gaseous carbon dioxide (C0.) and gaseous water...


CH(CH),CH) will react with gaseous oxypen (0) to produce gaseous carbon dioxide (C0.) and gaseous water (H,0). Suppose 41.9 G
CH(CH),CH) will react with gaseous oxypen (0) to produce gaseous carbon dioxide (C0.) and gaseous water (H,0). Suppose 41.9 Gaseous butane of butane is mixed with 59.7 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 3 significant digits. 5 ?
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Answer #1

2C4H10 + 13O2 = 8CO2 + 10H2O

number of moles of butane = 41/58 = 0.71 moles

number of moles of oxygen = 59.7/32 = 1.86 moles

for 1 mole of butane we need 5.5 moles of oxygen

1.86/5.5 = 0.34

we have only enough oxygen to react with 0.34 moles of butane

oxygen is the limiting reagent

number of moles of CO2 = 4 x 0.34 = 1.36 moles

mass of CO2 =1.36 x 44 =59.84 g

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