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How many grams of CaH2CaH2 are needed to generate 146 LL of H2H2 gas if the...

How many grams of CaH2CaH2 are needed to generate 146 LL of H2H2 gas if the pressure of H2H2 is 826 torr at 20 ∘C∘C?

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Answer #1

PV = nRT n= PV RT mole = Pressure x Volume gas constant & Temperature (K) = $ 1826 latm x 1461 0.0821 latm/molk X (20+273)k m

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