Question

The figure shows a segment of a circuit with a resistor and an inductor. The current (in the direction shown) changes in time as shown in the graph of current as a function of time.

Rank (delta) Vba at the five times shown from most positive to most negative.

Rank (delta) Vdc at the five times shown from most positive to most negative.

The figure shows a segment of a circuit with a resistor and an inductor. The current (in the direction shown) changes in time as shown in the graph of current as a function 8 3. of time a. Rank AVba -Vb-Va (the voltage across the inductor) at the five times shown (A-E) from most positive to most negative (do take care with the sign of the voltage difference across the inductor). Rank (A-E) from most positive to most negative (do take care with the sign of the voltage across the resistor). b. AVoc Va- Vc (the voltage across the resistor) at the five times shown

Answer 1

Given the figure shows a segment of a circuit with a resistor and an inductor changes in time as shown in the graph of current as a function of time. a) The voltage across an inductor is given by V = L dI/dt and the terminal at which the current enters is considered more positive. It is hence the slope of the given It curve which determines the magnitude of the voltage Vb - Va across the inductor. As can be seen from the curve, the slope is zero at time instant c, positive at A and B and negative at D and E. Also the slope at B is greater than that at A and the slope at D is more negative than that at E. Therefore the voltage in decreasing order of magnitude are at the time instants B, A, C, E and lowest \r\n or most negative at D. b) The potential across a resistor is given by