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Could somebody help me with this question for the coding on MATLAB? Thank you

Projectile Motion The distance a projectile travels when fired at an angle Θ is a function of time and can be divided into horizontal distance, dVotcos(O) and the vertical distance is dy Vot sin(0)-0.5gt2. Suppose a projectile is fired at an initial velocity of 100 m/s and a launch angle of /4 radians (45°). Use ezplot to graph horizontal distance on the x -axis and vertical distance on the y -axis for times from 0 to 20 seconds. V(t) 1 h(t)

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Answer #1

v0=100;
theta=pi/4;
g=9.81;

syms t
dx=v0*t*cos(theta);
dy=v0*t*sin(theta)-0.5*g*t*t;

ezplot(dx,dy,[0,20])

MATLAB R2017a Search Documentation Log In Compare Go To▼ Comment ge-ese Breakpoints Run Run and ES Advance ▼ New Open Save Figure 1 Indent E Print Find ▼ Advance File Edit View Insert Tools Desktop Window Help Current Folder Editor-GAMATLAB\R2017a\bin\UntitledT9.m x-50 21/2 t y = 50 2112 t-(981 t2)/200 400 田山html ㄧ田ぷm3iregistry -v0-100 2-theta-pi/4; 3-g-9.81: profile-results registry 200 田山util 田山win64 5-yms t 6- dx=vo*t* cos(theta); 7-dy-vo*t*sin (theta)-0.5*g*t*t: mbuild.bat 9ezplot (dx, dy, [o,20]) mex.bat mexext.bat 200 worker.bat lena.bmp 400 Details Works Name- 600 Command Window 200 600 1000 1200 00 3.1416 1x1 sym x1 sym 9.8100 1x1 sym 0.7854 100 400 800 >> pi dy 3.1416 Activate Windows Go to PC settings to activate Windows Untitled79 Ln 9 Col 19

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