1. t1/2 is the time required to reduce half of the initial concentration
from the graph intial conc [Ao] = 0.18 M
half of inital conc = 0.18/2 = 0.9 M
from the graph time at 0.9 M conncentration is = 0.5 s
so t (half) = 0.50 s
2.
Rate constant = 0.693 / t(half) = 0.693 / 0.50 s = 1.386 s-1 ~ 1.39s-1
3.
![M To find the final concentreation of first order reaction First order rate constant K 1.386 S-1 Initial concentration [AO] 0](http://img.homeworklib.com/questions/a4f9fd20-b149-11eb-a49d-9dc1c125067d.png?x-oss-process=image/resize,w_560)
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