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The final exam scores of students taking a statistics course are normally distributed with a population mean of 72 and a popu

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Answer #1

Here, μ = 72, σ = 8, x1 = 60 and x2 = 84. We need to compute P(60<= X <= 84). The corresponding z-value is calculated using Central Limit Theorem

z = (x - μ)/σ
z1 = (60 - 72)/8 = -1.5
z2 = (84 - 72)/8 = 1.5

Therefore, we get
P(60 <= X <= 84) = P((84 - 72)/8) <= z <= (84 - 72)/8)
= P(-1.5 <= z <= 1.5) = P(z <= 1.5) - P(z <= -1.5)
= 0.9332 - 0.0668
= 0.8664

Option C

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