

4. A 20 mL wastewater sample was mixed with 280 mL deionized (DI) water in a...
QUESTION1 A 15-mL sample is added to à 300-ml 8OD bottle. Dilution water is added to the sample bottle and the initial dissoved axygen concentration is measured as 8.5 mg/L. After the sample is sealed, the laboratory incorrectly takes a measurement of dissolved oxygen reading on day 6 of 3 mg/L. If the BOD reaction rate coefticient for the sample is 0.30/day, estimate what the 5-day BOD should have been QUESTION 2 A 15-mL sample is added to a 300-mL...
A BOD test is run with 150 mL of wastewater mixed with 150 mL of deionized water. The initial DO = 8.5 mg/L, the DO after 5 days = 4.2 mg/L, and the DO ultimately levels off at 1.7 mg/L. Assume all nitrification has been inhibited and the temperature remains constant. a) Calculate the CBOD5 (y5, mg/L) b) Calculate the ultimate CBOD (Lo, mg/L) c) Calculate the CBOD remaining after 5 days (L5, mg/L) d) Calculate the deoxygenation rate constant...
Problem 4 (10 Points). You collect a sample of wastewater and run a BOD test. To run this test, you mix 25 mL of the wastewater sample with clean (unseeded) dilution water to bring the total volume in the bottle to 300 ml, After measuring the initial dissolved oxygen concentration, you cap the BOD bottle and monitor the dissolved oxygen concentration of the diluted sample in the BOD bottle as a function of time (see Figure below). Previous tests have...
0. What is the BODs of the wastewater sample if the DO values for the blank and diluted samples afher 5 days are R1 mg/L and 3.5 mg/L, respectively, and the wastewater is diluted from 2 miL to 200 milL? (10 points) If the 20 day BOD (assume that this is the ultimate BOD) is 700.0 mg/L determine the BOD rate constant k (in base e). (10 points)
0. What is the BODs of the wastewater sample if the DO...
ml of river water with BODs of 1000 ppm is diluted to 1 L, aerated and seeded. The If 2 disolved oxygen content was 7.8 mg/L initially. After 20 days, the dissolved oxygen ssolv content had dropped to 5.3 mg/L. What is the ultimate BOD, and remaining BOD? Which of the two BODs give better prediction of BODL, and why?
ml of river water with BODs of 1000 ppm is diluted to 1 L, aerated and seeded. The If 2...
2. To determine the BOD in an industrial wastewater sample, a seeded BOD analysis was conducted; data are summarized in the table below. Ten mL of wastewater was added per 300 mL bottle to determine the dissolved oxygen demand of the aged, settled wastewater seed (test A). The seeded test bottles (test B) contained 2.5 mL of industrial wastewater and 1.2 mL of seed wastewater a) What is the five-day BOD in this industrial wastewater? What is the k-value using...
7. A BOD test is run using 100 mL of treated wastewater effluent mixed with 200 mL of dilution water (containing no BOD). The initial DO of the mix is 9.0 mg/L After 5 days, the DO is 4.0 mg/L. After a long period of time, the DO is 2.0 mg/L, and it no longer seems to be dropping. Assume nitrification has been inhibited so that only carbonaceous BOD is measured (a) What is the 5-day BOD of the wastewater?...
Please answer #5
4. What is the theoretical oxygen demand for a wastewater flow of 25 MGD (million gallons per day) containing 100 mg/L ethanol (C2H5OH)? 5. If this wastewater was discharged into a stream flowing at 10 m/s with an ultimate BOD of 5 mg/L, dissolved oxygen (DO) of 5mg/L, and deoxygenation rate coefficient ka of 0.2/day: (a) Find ultimate BOD of mixture just downstream of wastewater discharge. State all assumptions used. (b) In your opinion, is the wastewater...
While interning at a wastewater treatment plant, you conduct a seeded BOD5 test of the lant's effluent. For the experimental bottle, you insert 30 mL of test sample into the 300-mL ottle and fill the rest with seeded dilution water. You fill a blank bottle with seeded dilution ater. You measure the following dissolved oxygen (DO) concentrations at the start and end f the 5-day test: Bottle Initial DO (mg/L) Final DO (mg/L) Experimental 8.1 4.6 Blank 7.8 6.7 hat...
ENV3006C HW#4 The following data provided to you. Calculate the BODS of the WW sample (mg/L) are Seeded wastewater (WW): Initial DO 8.2 mg/L; Volume of wastewater Final DO (after 5 days) 2.5 mg/L Total volume in BOD bottle = 300 mL 5 mL Seeded dilution water: Final DO (after 5 days) 7.3 mg/L Initial DO 8.3 mg/L; Volume of seeded dilution water 300 mL