Question

What does the following nested loop structure output? count = 1; while (count <= 11) {innerCount = 1 while (innerCount <= (12 - count)/2) {cout << " "; innerCount++;} innerCount = 1; while (innerCount = 1; while (innerCount <= count) {cout << "0"; innerCount++;} cout << endl; count++;} What does the following nested loop structure output? count = 1; while (count <= 10) {innerCount = 1; while (innerCount <= 10) {cout << setw(5) << count * innerCount; innerCount++;} cout << endl; count++;} The following loop is supposed to sum all of the input values on file indata. What's wrong with it? Change the code so that it works correctly. sum = 0; indata >> number; while (indata) {indata >> number; sum = sum + number;}

Answer 1

1)

It print out the triange of @

What happen in code:

   int count = 1;
// loops untill 11
while(count <= 11)
{
int innerCount = 1;
// prints space " " . half the times of 12 - count
while(innerCount <= (12 - count) / 2)
{
cout << " ";
innerCount++;
}
innerCount = 1;
// prints the @ upto number of count
while(innerCount <= count)
{
cout << "@";
innerCount++;
}
cout << endl;
count++;
}

2)

It print out multiples of 1 to 10 upto 10 number and print in rows

Explaination?

int count = 1;
// loops untill 10
while(count <= 10)
{
int innercount = 1;
// loops untill 10 and print count*innercount
while(innercount <= 10)
{
cout << setw(5) << count * innercount;
innercount++;
}
cout << endl;
count++;
}

3)

indata >> number; was repeating twice so there is a chance of skipping first number.

so replace it with

sum = 0;

while(indata>>number)

{
sum = sum + number;
}//end while