Consider a beaker containing equal amounts of dihydrogen phosphate anhd hydrogen phosphate to which either a strong acid is added (Beaker C) or a strong base is added (beaker D).
1) Calculate the pH of the contents of beaker C
2) Calculate the pH of the contents of beaker D.

beaker C
moles of H2PO4- = 0.01
moles of HPO42- = 0.01
moles of acid added = 1 x 1 / 1000 = 0.001
pH = pKa + log [salt - C / acid + C]
= 7.21 + log [0.01 - 0.001 / 0.01 + 0.001]
= 7.12
pH = 7.12
beaker D
moles of base added = 1 x 1 / 1000 = 0.001
pH = pKa + log [salt + C / acid - C]
= 7.21 + log [0.01 + 0.001 / 0.01 - 0.001]
= 7.30
pH = 7.30
Consider a beaker containing equal amounts of dihydrogen phosphate anhd hydrogen phosphate to which either a...
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