Question

8) A positive test charge q is released near a positive fixed charge Q 2 As q moves away from Q, the force on q will A) decrease B) increase C) be constant
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Answer #1

Solution:

The force on q is given by,

=> F = k q1 q2 / r^2

as we can see from the formula, F is inversly dependent on r as the distance will increase the force will decrease.

Hence the Force on q will be decrease

option A should be right.

please rate thanks.

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