Question

# Review: Square Coil, Round Hole Due this Friday, Mar 29 at 11:59 pm (EDT) A square,... Review: Square Coil, Round Hole Due this Friday, Mar 29 at 11:59 pm (EDT) A square, single-turn wire coil L-1.42 cm on a side is placed inside a solenoid that has a circular cross section of radius r 2.71 cm, as shown in the figure below. The solenoid is 17.4 cm long and wound with 100 turns of wire. If the current in the solenoid is 2.72 A, find the flux through the coil Submit Answer Tries 0/10 If the current in the solenoid is reduced to zero in 2.59 s, calculate the magnitude of the average induced emf in the coil. Submit Answer Tries 0/10

a)

flux through the loop is given by

phi = BA = ( uo N i/L) A

phi = 4* 3.14* 10^-7* 100* 2.72 * (1.42*10^-2)^2 / (0.174)

phi = 3.96*10^-7 Tm^2

======

b)

emf induced

e = change in flux / time

e = (phi - 0) / t

e = 3.96*10^-7 / 2.59

e = 1.529*10^-7 V

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