Question

The velocity graph of an accelerating car is shown. v (km/h) 60 40 201 t(seconds) 12 18 (a) Estimate the average velocity Vave of the car during the first 18 seconds. Use the Midpoint Rule with n = 3. (Round your answer to the nearest whole number.) Vave = km/h (b) At what time t was the instantaneous velocity equal to the average velocity? (Round your answer to one decimal place.) S Need Help? Read it Talk to a Tutor

Answer 1

Answer 2

Qu (a) Use the Midpoint Rule to estimate the average velocity of the car during the first 18 seconds. Solution The Expression to find the average Valur of function Varg the Interval [a, b Vang f(x) dx On b-a Substitute o fos a and 18 for b in above equation 18 Vang a V(+) dt { "vendt Loli 18-0 18 We Applying midpoint rule as shown in below use mid point rule n=3 intervals find the value of at as shown in below b a 18 - O 6 n 3 find the value of ult) as Show below 18 VLt)dt = st + VLAX [V(659) V(12) + v(187"P)] V(A)dt = 6 ( v(3) + V(9) + + V(9) + VOS)] = b[ 12 Kalm javasot = Put the value of Lºve 4%! 6 + us km/h + 58 km/h 726 km/u in equation à

Varg & the live VG+) dt - X 726 40.3334 km In And 18 was Vang - 40.3334 km/h Ио km/h Ans (b) At what time at the instantaneous velocity equal to average velocity ? Solution From the braph, the velocity of no km/h Corresponds to time of about 7.5 seconds a t = 7.5 seconds Answer

AVERAGE VELOCITY IS 40 km/h

TIME IS 7.5 second

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