Question

Review Constants Periodic Tab (Figure 1) is the potential energy diagram for a 30g particle that is released from rest at 10 m Part A Will the particle move to the right in the positive direction or to the left in the negative direction, and why? Figure 1 of 1 Energy (J) • The particle will move to the left. Moving to the right requires the particle to have negative kinetic energy, which is impossible The particle will move to the right Moving to the left requires the particle to have negative kinetic energy, which is impossible The particle will move to the right. Moving to the left requires the particle to have negative potential energy, which is impossible The particle will move to the left. Moving to the right requires the particle to have negative potential energy, which is impossible Previous Correct 0 + 1567 Part

Please! Can anyone explain those answers to me? It would be better if you could demonstrate your process. Thanks!

Answer 1

B)

KE_max = PE_max = 4-1 = 3 J

KE = 1/2mv^2

3 J = 1/2*0.030 *v^2

v = 14.14 m/s

C)

at   x = 4 m the particle will have maximum speed

D)

turning point are   x = 6 m and x = 1 m