40) The force on the second are
kx - kq^2/R^2 = 0 ;
500 * (1-.5) = k q^2/R2
q = sqrt (250/9*109)
q = 167 uC
41 ) writing the similar equation
K ( .5 - R ) = k Q^2/R^2
250 R^2 - 500 R^3 = 9*109 * 9*10-10
250 R^2 - 500 R^3 = 8.1
Hence R = .259 m and 0.397 m
42 ) The similar equation just changes the sign
K ( R - .5) = k Q^2/R^2
250 R^2 + 500 R^3 = 9*109 * 9*10-10
R = 0.553 m
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"A horizontal spring with force constant k = 810 N/m is
attached to a wall on one end. The other end of the spring is
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countertop, as shown below."
Help with any or all of these would be greatly appreciated,
thank you!
3. [0/3 Points] DETAILS PREVIOUS ANSWERS SERCP11 13.4.OP.021. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER A horizontal spring with force constant k = 810 N/m is attached...
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