Question

Element Atomic Weight C 12 Ca 40 H 1 N 14 Na 23 O 16 A...

Element

Atomic Weight

C

12

Ca

40

H

1

N

14

Na

23

O

16

A 1 millimole/L Sodium Lactate (NaC3H5O3) solution would be equal to what mg% concentration?

47

4.8

33.6

3.6

4.7

2.3

11.2

36

22

9.9

14

48

5.6

2.2

23

0 0
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Answer #1

Molar mass of Sodium Lactate = 112 g/mol

1 milimol = 10-3 mol

1 milimol of Sodium Lactate = 112 x 10-3 g = 0.112 g = 112 mg

Therefore, 1 milimol/L Sodium Lactate = 112 mg of Sodium Lactate in 1 L.

1000 mL of solution contains Sodium Lactate = 112 mg

100 mL of solution contains Sodium Lactate = 11.2 mg

Hence, mg% concentration of the solution is 11.2 %.

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