Question

Part A A 60 inclined plane of length 0.30 m is positioned at the edge of a table that is 20 m high, as shown in Figure 1). A box is placed at the top of the plane and given a shove so that it has an initial velocity of 2.0 m/s down the plane. The coefficient of kinetic friction between the block and the plane is 0.80(a) Calculate the speed of the block when it reaches the bottom of the plane () Find the speed of the block when it is 0.70 m above the floor. (c) is the total mechanical energy of the block conserved as it moves from the top of the plane to the for Consider the orientation of the axes shown below. In this Problem, we should use two coordinate systems. The years of the first system points vertically upward, -axis points horizontal rightward. The axis of the other system is directed downward along the plane, and they-ari is perpendicular to the plane. We will us orientation of the axes throughout the problem Figure identify all of the forces acting on the box when it is on the plane. Select all that apply View Available Hint(s)

Answer 1

2 2 m/sec Apply Work Energy theorem Mgcos wod by sunt o masina gravity +W.D by friction UB - chang In KE VA= 2 m/sec A- Piezo 30 m fk = M N fk = ung caso - (ung.coso + yngsins)x0:30 1 4 = .80 => A( sino - MCOS)x0.30 = {108-4) = [UB = 2.60 m/sec) JUB= 2060 m/sec) B UB= 2060 m/sec 0.3 Ec=? Apply Energy conservation (BTC) EB = Ec (K•€ +P:[]g = (K.E+PE) I put ongel) = £ much + ing(0.70) I UB + 9(0.30) = ± 0,² 0.70ml PE=0 Vc = 3.55 msec o point A to B total mechanical Energy is not conservered because frictional force present while point B to floor total mechanical Energy esconservered