Question

FTY = 0 FEDSINTHETA - FBE + FECSINALPHA - FAESINTHETA = 0 FEDSIN26.56 - 7 -...

FTY = 0

FEDSINTHETA - FBE + FECSINALPHA - FAESINTHETA = 0 FEDSIN26.56 - 7 - FECSIN26.56 - 7.83*SIN26.56 = 0

FED + FEC = 23.485

FTX = 0

FAECOSTHETA + FECCOSALPHA - FEDCOSTHETA = 0 7.83COS26.56 + FECCOSALPHA - FEDCOSTHETA = 0

FEC - FED = -7.83

FED = 15.655 (compression)

FEC = 7.83 (tension)

could i have a break down of steps for the calculations please. how the answers 23.485 and -7.83 appear.

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Answer #1

What I can observe in the answer sub-part is that,

First, force in y-direction is balanced, and written as

FED*sin θ - FBE + FEC*in a - FAE*sin θ=0,

In the question somewhere it might be given as, heta=alpha=26.56, FBE=7, FAE=7.83

again, FED*sin 26.56 -7 + FEC*sin 26.56 - 7.83*sin 26.56=0

after solving, FED+FEC= 23.485 ............Equation 1

Similarly, Force in x-direction is balanced, and written as

FAE*cos heta + FEC*cos alpha - FED*cos heta=0,

In the question somewhere it will be given as, heta=alpha=26.56, FAE=7.83

7.83*cos 26.56 + FEC*cos 26.56 - FED*cos 26.56=0

Hence, FEC-FED= -7.83 ................... Equation 2

After soling Equation 1&2,

We get, FED= -15.655= 15.655 (Compression)

and, FEC= +7.83 = 7.83 (Tension)

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