Homework Answers
Two 20g ice cubes = 40g / 18.0-g/mol = 2.22 mol
water moles = 285 / 18.0 = 15.82 mol water
(2.22 x 18 °C x 37.7) + (2.22 x 6010) + [2.22 x (Tf - 0 °C) x 75.3]
= 15.82 x (25 °C - Tf) x 75.3
1506.49 + 13342.2 + 163.17Tf = 29781.15 - 1191.25
Tf
14848.69 + 163.17Tf = 29781.15 - 1191.25 Tf
Tf = 11.02
final temperature of the water = 11.0 °C
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