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- X 0 0 0 De 14 the -1- . .


| X9 0 0


Use this circult to answer Questions 13-16: Use Theveninto culte voltage V. at the load for the circuit below with V, 220 V Z
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Answer #1

Vs = v2Lov, 21 = j) , 22=1, Z2 = 0.5+j0,5 리 Va Z24 13) Thevening open circuit Voltage across arb Wab):- * Open circuit ? acroCorrect option is @ 11-45° 0 14) Thevening Empedance across (916) Rab :- * short arcuit Voltage source (us) and circuit iz th15) Thevenins equivalent drawn as Kaь 1. Z Kab 02 ② Vab current through when load disconnected impedance Zz 58 VS A Z + Z2 It* Converting polar to Pectangular farin 1 150 1605 450 + i sin ase) (! +9+0.5+jo.5 1/-450 2 Ty = L L-45° { = 1.450 { = 1 1 2

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